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如何证明这个薛定格方程没有束缚态?
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轩轩 发表文章数: 1352 |
如何证明这个薛定格方程没有束缚态? 谐振子是H=p^2+x^2当然有束缚态 if H=p^2+x^-2 则没有束缚态 为什么呀 大家随便谈谈吧 我无知到了只懂相对论了。 http://zhangxuanzhong.blog.edu.cn/ 《相对论通俗演义》 i will love you till the null infinity.
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雪云居 发表文章数: 205 |
Re: 如何证明这个薛定格方程没有束缚态? whether it is because of the uncertainty principle ? 数学和物理学的精确与深邃,历史的变幻,唐诗宋词的典雅,中国古代哲人的睿智,都是我内心渴望追求的。 知无可奈何而安之若素,德之至也!
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sage 发表文章数: 1125 |
Re: 如何证明这个薛定格方程没有束缚态? let's just prove that the ground state is not a bound state. 1) bound state wavefunction must vanish at infinity. 2) ground state is the lowest energy state. 3) for 1/x^2 potential, you can alway get lower energy by pushing your wave-function further away. 4) therefore, ground state wave-function does not vanish at infinity 5) therefore, it is not a bound state.
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轩轩 发表文章数: 1352 |
Re: 如何证明这个薛定格方程没有束缚态? thanks sage , you are always my teacher in physics.:) then , when the X---->infinity ,the hamitonian is describing the free particle in the case .so the eigenvalue isn't discrete ???? en , if the potential part becomes x^2+x^-2. can you figure out the spetrum? 我无知到了只懂相对论了。 http://zhangxuanzhong.blog.edu.cn/ 《相对论通俗演义》 i will love you till the null infinity.
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sage 发表文章数: 1125 |
Re: 如何证明这个薛定格方程没有束缚态? >then , when the X---->infinity ,the hamitonian is describing the free particle in the case . >so the eigenvalue isn't discrete ???? ===================================================================== correct. it is continuous. >en , if the potential part becomes x^2+x^-2. can you figure out the spetrum? ===================================================================== I will leave it to you as an excercise. hint: the schrodinger equation here is the same as the one for the radial wave-function of three-dimensional harmonic oscillator.
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yinhow 发表文章数: 727 |
Re: 如何证明这个薛定格方程没有束缚态? en , if the potential part becomes x^2+x^-2. can you figure out the spetrum? 这个可以用代数方法来解决,代数结构是su(1,1),从它的表示理论可以读出它的谱来. Wealth in sufficient measure grants its possessors the right to their ensuthisams.
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轩轩 发表文章数: 1352 |
Re: 如何证明这个薛定格方程没有束缚态? en , if the potential part becomes x^2+x^-2. can you figure out the spetrum? 这个可以用代数方法来解决,代数结构是su(1,1),从它的表示理论可以读出它的谱来. 为什么说是su(1,1),如何看出来的???如何定义它的升降算子??? 我无知到了只懂相对论了。 http://zhangxuanzhong.blog.edu.cn/ 《相对论通俗演义》 i will love you till the null infinity.
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yinhow 发表文章数: 727 |
Re: 如何证明这个薛定格方程没有束缚态? 为什么说是su(1,1),如何看出来的???如何定义它的升降算子??? 还可以定义su(1,1)的相干态 下午我发邮件给你. Wealth in sufficient measure grants its possessors the right to their ensuthisams.
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